SOLUTION: Write the complex number in the form a + bi. square root of six (cos 315° + i sin 315°)

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Question 1134041: Write the complex number in the form a + bi.
square root of six (cos 315° + i sin 315°)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the complex number in the form a+%2B+bi.
sqrt%286+%28cos+%28315%29+%2B+i+%2Asin+%28315%29%29+%29.......cos+%28315%29+=1%2Fsqrt%282%29 and sin%28315%29=+-1%2Fsqrt%282%29
=sqrt%286+%281%2Fsqrt%282%29-+i+%2A1%2Fsqrt%282%29%29+%29
=sqrt%286+%281-+i+%29%2Fsqrt%282%29+%29
=sqrt%28+6+%281-+i+%29%2Fsqrt%282%29+%29
=sqrt%28%28sqrt%282%29%2A6+%281-+i+%29%29%2F2+%29
=sqrt%28sqrt%282%29%283+-+3i+%29%29
=root%284%2C2%29%2Asqrt%283%281+-+i%29+%29
=root%284%2C2%29%2Asqrt%283%29sqrt%281+-+i+%29
=1.18920%2A1.732%281.0986841+-0.455%2Ai%29
=2.26+-+0.937%2A+i