SOLUTION: Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 62 feet

Algebra ->  Rectangles -> SOLUTION: Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 62 feet      Log On


   

Question 1134013: Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 62 feet
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions x and 2x+1, and x%2B%282x%2B1%29=62%2F2=31; solve and evaluate.