SOLUTION: An object is launched upward from the groumf an initial velocity of 200 ft/sec. The height h(in feet)of the object after t sec is given by h(t) = - 16t^2+200t. a) Find the heigh

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: An object is launched upward from the groumf an initial velocity of 200 ft/sec. The height h(in feet)of the object after t sec is given by h(t) = - 16t^2+200t. a) Find the heigh      Log On


   



Question 1133993: An object is launched upward from the groumf an initial velocity of 200 ft/sec. The height h(in feet)of the object after t sec is given by h(t) = - 16t^2+200t.
a) Find the height of the object after 1 sec.
b) Find the height of the object after 4 sec.
c) When is the object 400 ft above the ground?
d) How long does it take for the object to hit ground?

Answer by Glaviolette(140) About Me  (Show Source):