SOLUTION: Sue has $2.60 in dimes and nickels. If she has 11 more dimes than nickels, how many of each coin does she have?

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Question 1133863: Sue has $2.60 in dimes and nickels. If she has 11 more dimes than nickels, how many of each coin does she have?
Found 3 solutions by Boreal, josgarithmetic, greenestamps:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=nickels
x+11=dimes
.05x+.10(x+11)=2.60 (money equation)
.05x+.10x+1.10=2.60
.15x=1.50
x=10 nickels(50 cents)
x+11=21 dimes (210 cents)
add to 260 cents or $2.60

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%2810d%2B5n=260%2Cd-n=11%29

-

system%282d%2Bn=52%2Cd-n=11%29

Add corresponding members.
3d=63
highlight%28d=21%29----------------highlight%28n=10%29

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


This kind of problem can be solved informally using logical reasoning.

(1) Set aside the 11 "extra" dimes. What remains is equal numbers of dimes and nickels with a total value of $2.60-$1.10 = $1.50.
(2) The value of one dime and one nickel is 15 cents, or $0.15.
(3) To make the remaining $1.50, the number of dimes and nickels required is $1.50/$0.15 = 10.

So there are 10 nickels and 10+11=21 dimes.