SOLUTION: A DVD rotates at an angular frequency of 4800 rpm. a) at 4800 rpm, what is the linear speed (in km/hr) off (i) the center point and points (ii) 5cm and (iii) 6cm from the center?
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-> SOLUTION: A DVD rotates at an angular frequency of 4800 rpm. a) at 4800 rpm, what is the linear speed (in km/hr) off (i) the center point and points (ii) 5cm and (iii) 6cm from the center?
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Question 1133773: A DVD rotates at an angular frequency of 4800 rpm. a) at 4800 rpm, what is the linear speed (in km/hr) off (i) the center point and points (ii) 5cm and (iii) 6cm from the center? Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! linear speed(v) = circumference of circle of radius r/time(t) = (2*pi*r)/t
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i) r = 0, then v = 0 km/hr
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ii) r = 5 cm
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distance in 1 hour is (2 * pi * 5) * 4800 * 60 = 9047786.8423 cm is approximately 9047787 cm = 90477.87 m = 90.5 km/hr
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iii) r = 6 cm
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distance in 1 hour is (2 * pi * 6) * 4800 * 60 = 10857344.2108 cm is approximately 108.6 km/hr
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