SOLUTION: A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 576t. After how many seconds does the projectile take to
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-> SOLUTION: A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 576t. After how many seconds does the projectile take to
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Question 1133704: A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 576t.
After how many seconds does the projectile take to reach its maximum height?
:
Max occurs on the axis of symmetry, use the formula x = -b/(2a)
where: a=-16; b=576
t =
t = 18 seconds to reach max height
