Question 1133405: find the equation of the line that passes through (3,-1) and is perpendicular to the line that passes through (-5,2) and (-1,7).
please show work thank you!!
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! find the equation of the line that passes through (3,-1) and is perpendicular to the line that passes through (-5,2) and (-1,7).
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Step 1, find the slope of the line thru the points.
Step 2, lines perpendicular have a slope that's the negative inverse.
step 3, use
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y-y1 = m*x-x1) where m = slope and (x1,y1) is the point (3,-1)
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I'll do a similar problem:
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find the equation of the line that passes through (2,-2) and is perpendicular to the line that passes through (-1,3) and (-2,-3).
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find the slope of the line m1
m1 = diffy/diffx = -6/-1 = 6
Slope of lines perpendicular m2 = -1/m1 = -1/6
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y+2 = (-1/6)*(x-2)
PS It's not "the equation," it's an equation.
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email via the TY note to check your work.
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