SOLUTION: if x is a real number, then what is the minimum value of 3^(x^2-4x+8)

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Question 1133288: if x is a real number, then what is the minimum value of 3^(x^2-4x+8)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The minimum value of x^-4x+8 occurs at the vertex where =-b/2a or -4/-2 or 2
x=2, f(x)= 4 and the value is 3^4=81.
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