SOLUTION: Urn 1 contains 6 red balls and 5 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 3 contains 2 red balls and 6 black bal
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-> SOLUTION: Urn 1 contains 6 red balls and 5 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 3 contains 2 red balls and 6 black bal
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Question 1133274: Urn 1 contains 6 red balls and 5 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 2 contains 3 red balls and 3 black balls. Urn 3 contains 2 red balls and 6 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! probability is 1/3 for each urn.
for urn 1: (1/3)(6/11)=6/33 or 2/11
for urn 2:(1/3)(1/2)=1/6
for urn 3:(1/3)(1/3)=1/9
The probability is the sum with LCD 198
(1/198)(36+33+22)or 91/198 or 0.4596
