SOLUTION: Solve the equation after making an appropriate substitution. (3t-5)^2-11(3t-5)+10=0
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Question 1133269
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Solve the equation after making an appropriate substitution.
(3t-5)^2-11(3t-5)+10=0
Answer by
Boreal(15235)
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(3t-5)^2-11(3t-5)+10=0 Let x=3t-5
then x^2-11x+10=0
and (x-10)(x-1)=0
x=10 and x=1
3t-5=10
3t=15
t=5
3t-5=1
3t=6
t=2