SOLUTION: Determine if limx→0 f(x) exists. Is the function continuous at x = 0? f(x) = −x + 1 if x ≤ 0 2x + 3 if x > 0 (it is a piecewise function)
Algebra
->
Distributive-associative-commutative-properties
-> SOLUTION: Determine if limx→0 f(x) exists. Is the function continuous at x = 0? f(x) = −x + 1 if x ≤ 0 2x + 3 if x > 0 (it is a piecewise function)
Log On
Algebra: Distributive, associative, commutative properties, FOIL
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Distributive-associative-commutative-properties
Question 1133186
:
Determine if limx→0 f(x) exists. Is the function continuous at x = 0?
f(x) =
−x + 1 if x ≤ 0
2x + 3 if x > 0
(it is a piecewise function)
Answer by
greenestamps(13203)
(
Show Source
):
You can
put this solution on YOUR website!
The limit as x approaches 0 from the left is 0+1=1; the limit as x approaches 0 from the right is 2(0)+3 = 3.
Since the limits approaching 0 from opposite sides are different, the limit as x approaches 0 does not exist, and the function is not continuous.