SOLUTION: A 32 year old mother realized that her age is twice the sum of her two children's ages. Her son, jose is two years older than her daughter,sophia. How old are sophia (x) and jose (

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Question 1133125: A 32 year old mother realized that her age is twice the sum of her two children's ages. Her son, jose is two years older than her daughter,sophia. How old are sophia (x) and jose (y)?
Answer by addingup(3677) About Me  (Show Source):
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y = x + 2
2(x+x+2) = 32
2x+2x+4 = 32
4x = 28
x = 7 Sophia is 7
Jose is two years older: 7 + 2 = 9 Jose is 9
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Check:
Mother's age is twice the sum of her two children's ages:
(7+9)*2 = 32 Correct