SOLUTION: The sides of a right triangle are x, x+5, and x+6. If the length of the longest side is x+6, what is the value of x to make the triangle a right triangle?
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-> SOLUTION: The sides of a right triangle are x, x+5, and x+6. If the length of the longest side is x+6, what is the value of x to make the triangle a right triangle?
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Question 1132858: The sides of a right triangle are x, x+5, and x+6. If the length of the longest side is x+6, what is the value of x to make the triangle a right triangle? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x^2+(x+5)^2=(x+6)^2
x^2+x^2+10x+25=x^2+12x+36
x^2-2x-11=0
x=(1/2)(2+/- sqrt(4+44); sqrt 48=4 sqrt (3)
x=1+2 sqrt(3) or numerically is 4.464
sides are 4.46, 9.46, 10.46
