SOLUTION: This is the problem. y=x-1 4x-y=19 This is what I tried. 4x-x-1=19 3x-1=19 3x=20 x=6 and 2/3 Thank you very much!

Algebra ->  Expressions-with-variables -> SOLUTION: This is the problem. y=x-1 4x-y=19 This is what I tried. 4x-x-1=19 3x-1=19 3x=20 x=6 and 2/3 Thank you very much!       Log On


   

Question 113282: This is the problem.
y=x-1
4x-y=19
This is what I tried.

4x-x-1=19
3x-1=19
3x=20
x=6 and 2/3
Thank you very much!
Found 2 solutions by jim_thompson5910, solver91311:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the given system
4x-y=19
y=x-1



4x-%28x-1%29=19 Plug in y=x-1 into the first equation. In other words, replace each y with x-1. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.


4x-x%2B1=19 Distribute the negative


3x%2B1=19 Combine like terms on the left side


3x=19-1Subtract 1 from both sides


3x=18 Combine like terms on the right side


x=%2818%29%2F%283%29 Divide both sides by 3 to isolate x



x=6 Divide




Now that we know that x=6, we can plug this into y=x-1 to find y



y=%286%29-1 Substitute 6 for each x


y=5 Simplify


So our answer is x=6 and y=5

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
4x-x-1=19 You have one little 'oops' right here. It should be 4x-%28x-1%29=19
3x-1=19 That makes this look like: 3x%2B1=19
3x=20 So 3x=18
x=6 and 2/3, So x=6

You also need to substitute your newly found value for x back into one of the original equations to solve for y.

y=x-1
y=6-1=5

So the point of intersection of the two lines is (6,5)

Hope this helps,
John