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Question 11328: Mr. X operates a soybean farm. To keep costs down, he buys many products in bulk and transfers them to smaller containers for use on the farm. Often the bulk products are not the correct concentration and need to be custom mixed before Mr. X can use them. One day he wants to apply fertilizer to a large field. A solution of 74% fertilizer is to be mixed with a solution of 53% fertilizer to form 42 liters of a 63% solution. How much of the 74% solution must he use?
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! In the UK, these sort of questions are not common, but there seems to be a lot of these on this site, and they are quite straightforward, really.. so here goes:
Let x = amount of 74% solution.
so, we have 74% amount + 53% amount = 63% amount. The problem is, we are not told how much of the 53% solution was used... call this y for now.
0.74x + 0.53y = 42*0.63
now, x+y=42, so y=42-x, so use this rather than y, giving:
0.74x + 0.53(42-x) = 42*0.63
0.74x + 22.26 - 0.52x = 26.46
0.21x + 22.26 = 26.46
0.21x = 4.20
--> x = 20 litres.
jon.
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