SOLUTION: The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD, CE, and DE respectively. Find CD and DE if CF=8 cm

Algebra ->  Triangles -> SOLUTION: The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD, CE, and DE respectively. Find CD and DE if CF=8 cm       Log On


   



Question 1132732: The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD, CE, and DE respectively. Find CD and DE if CF=8 cm and EF=12 cm.
Answer by MathLover1(20850) About Me  (Show Source):
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A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N+lie on the sides CD , CE , and DE respectively.

Since, in rhombus, the opposite edges are parallel,
MFDE
=>CM%2FMD=CF%2FEF+
since given that CF=8cm and EF=12cm+, we have
=>+CM%2FMD=8%2F12
That is, CM=8 and MD=+12
Therefore, CD=CM%2BMD=8%2B12=20
But According to the question,
CD%2BDE%2BCE=55
=>20%2BDE%2B20=55
=> DE=15

Answer: CD=+20cm+and DE=+15cm