f(x)=x2+bx+4
does not intersect the x-axis. Which of the following must be true about b? Found 2 solutions by ankor@dixie-net.com, MathTherapy:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! In the xy-plane, the graph of the function
f(x)=x^2+bx+4
does not intersect the x-axis. Which of the following must be true about b?
:
Using the rules of the discriminant b^2 - 4ac < than 0, no real solutions
therefore
b^2 < (4*1*4)
b^2 < 16,
-4 > b < +4 will not intersect the x axis
You can put this solution on YOUR website!
In the xy-plane, the graph of the function
f(x)=x2+bx+4
does not intersect the x-axis. Which of the following must be true about b?
