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Question 1132486: A father distributes R1500 to his children, Jane, Karen and Eddie, in the ration J:K:E, respectively. If Jane gets twice as much as Karen, who in turn gets three times as much as Eddie, how much does each child receive?
Answer by ikleyn(52790)   (Show Source):
You can put this solution on YOUR website! .
Let x be the amount received by Eddie.
Then Karen received 3x, while Jane received 2*(3x) = 6x.
The total is
x + 3x + 6x = 1500.
10x = 1500 ====> x =  = 150.
Answer. Eddie received R150; Karen received 3*R150 = R450; Jane received 2*R450 = R900.
CHECK. 150 + 450 + 900 = 1500. ! Correct !
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Regarding your formulation, you can omit this part "in the ration J:K:E, respectively" totally.
It does not carry any info and is excessive.
A true Math problem formulation should not contain excessive parts, words, etc.
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