SOLUTION: When given the equation of the line that goes through (6,-10) and is perpendicular to 2y - 3x - 8 = 0, find the value of y + (2/3)x - 4.

Algebra ->  Rational-functions -> SOLUTION: When given the equation of the line that goes through (6,-10) and is perpendicular to 2y - 3x - 8 = 0, find the value of y + (2/3)x - 4.      Log On


   

Question 1132462: When given the equation of the line that goes through (6,-10) and is perpendicular to 2y - 3x - 8 = 0, find the value of y + (2/3)x - 4.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
When given the equation of the line that goes through (6,-10) and is perpendicular to 2y+-+3x+-+8+=+0, find the value of y + (2/3)x - 4 ?????????=> it’s unclear what this means
you are given: the line that goes through (6,-10) and is perpendicular to 2y+-+3x+-+8+=+0
so, all you can do is to find equation of that line

2y+-+3x+-+8+=+0...write it in slope intercept form
2y+=3x%2B+8+
y+=%283%2F2%29x%2B+4+=> slope is m=3%2F2
perpendicular line will have a slope negative reciprocal which is -2%2F3
if the line that goes through (6,-10), we can use point slope formula to find equation:
y-y%5B1%5D=m%28x-x%5B1%5D%29
y-%28-10%29=-%282%2F3%29%28x-6%29
y%2B10=-%282%2F3%29x-%282%2F3%29%28-6%29
y=-%282%2F3%29x%2B%282%2Fcross%283%29%29%28cross%286%292%29-10
y=-%282%2F3%29x%2B4-10
y=-%282%2F3%29x-6