SOLUTION: the link below is the pic of my question https://scontent.fgum3-1.fna.fbcdn.net/v/t1.15752-9/49567314_404049103667943_6002366669043793920_n.jpg?_nc_cat=100&_nc_ht=scontent.fgum3

Algebra ->  Geometry-proofs -> SOLUTION: the link below is the pic of my question https://scontent.fgum3-1.fna.fbcdn.net/v/t1.15752-9/49567314_404049103667943_6002366669043793920_n.jpg?_nc_cat=100&_nc_ht=scontent.fgum3      Log On


   

Question 1132363: the link below is the pic of my question
https://scontent.fgum3-1.fna.fbcdn.net/v/t1.15752-9/49567314_404049103667943_6002366669043793920_n.jpg?_nc_cat=100&_nc_ht=scontent.fgum3-1.fna&oh=086e313e69e147d27ef5f91380449f00&oe=5CCC9CDA
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


None of the choices is correct.

SAS requires two sides and the included angle; ASA requires two angles and the included side.

The given information only gives one pair of congruent sides and one pair of congruent angles. That is not enough in any situation.

It LOOKS AS IF point J is the intersection of segments IL and HK; that would make angles IJH and KJL congruent, and then B would be the right answer. But they don't tell us that J is the intersection of IL and HK, so we can't assume it.

It looks to me like a carelessly presented problem.