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Please notice on how I edited your post to make it readable.
Given: ABCD is a parallelogram with m (< A) = m (< D). Prove: ABCD is a rectangle.
Solution
In any parallelogram, the sum of the measures of two consecutive angles is equal to 180 degrees.
So, m (< A) + m(< D) = 180 degrees, and
m(< A) = M(< D). ( <<<---=== given ! )
Therefore, m(< A) + m(< A) = 180 detrees, or
2m(< A) = 180 degrees, which implies m(< A) = 90 degrees.
Thus in our parallelogram one angle is 90 degrees.
It means that EACH angle of the given parallelogram is 90 degrees, and hence the parallelogram is a rectangle.
Proved, solved and completed.