SOLUTION: Amina bibi has prepared masonry mixture with sand and cement in a ratio of measurement 7:1. But after the brick-work it is seen that 72 kg of mixture remains. She has added more ce

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Question 1132188: Amina bibi has prepared masonry mixture with sand and cement in a ratio of measurement 7:1. But after the brick-work it is seen that 72 kg of mixture remains. She has added more cement with this mixture and the ratio of measurement of sand to cement becomes 6:1. Let’s work out the total quantity of cement she has mixed.
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i think you're asking how much cement was added to 72 kilograms of the mixture to make the ratio of sand to cement = 6/1 rather than 7/1.

the ratio starts at 7 to 1.

that means 7 parts out of 8 is sand and 1 part out of 8 is cement.

the total number of parts is 8.

72 / 8 = 9

each part is worth 9 kilograms.

7 * 9 = 63 kilograms of sand.

1 * 9 = 9 kilograms of cement.

72 kilograms of mix is equal to 63 kilograms of sand and 9 kilograms.

you add x kilograms of cement to the mixture.

you now have 63 kilograms of sand and 9 + x kilograms of cement.

the ratio of sand to cement is now 6 to 1 rather than 7 to 1.

63 / (9 + x) = 6 / 1

multiply both sides of this equation by (9 + x) to get 63 = 6 * (9 + x) / 1

simplify to get 63 = 54 + 6x

subtract 54 from both sides to get 63 - 54 = 6x

combine like terms to get 9 = 6x

divide both sides by 6 to get 9 / 6 = x which makes x = 1.5 kilograms.

the amount of cement that is added to the mixture is 1.5 kilograms.

you now have 63 kilograms of sand and 9 + 1.5 = 10.5 kilograms of cement.

the new mixture contains 63 kilograms of sand and 10.5 kilograms of cement which is equal to a total mixture of 73.5 kilograms.

the sane to cement ratio is now 63 / 10.5 = 6 / 1.


Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
So, we have 72 kg of the mixture containing sand and cement in the ratio 7:1.


It means that there are 7+1 = 8 parts of the equal mass; each mass is  72%2F8 = 9 kilograms.


So, there are 7*9 = 63 kilograms of the sand and 9 kilograms of the cement in the original mixture.


We want to add "x" kilograms of the cement to get the ratio  sand to cement 6:1.


    63%2F%289%2Bx%29 = 6%2F1  ====>

    63 = (9+x)*6

    63 = 54 + 6x

    x = %2863-54%29%2F6 = 9%2F6 = 1.5 kilograms of cement to add.    ANSWER


CHECK.  63%2F%289%2B1.5%29 = 63%2F10.5 = 6.    ! Correct !

Solved.

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There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - Advanced mixture problems
    - Advanced mixture problem for three alloys
    - OVERVIEW of lessons on word problems for mixtures
in this site.

A convenient place to quickly observe these lessons from a  "bird flight height"  (a top view)  is the last lesson in the list.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

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