SOLUTION: Solve for 0° ≤ θ ≤ 360°: 2cosēθ - 3sin2θ - 2 = 0

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Question 1132133: Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 = 0
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solve for 0° ≤ theta ≤ 360°:
2cos%5E2%28theta%29+-+3sin%5E2%28theta%29+-+2+=+0+
-+2%2B2cos%5E2%28theta%29+-+3sin%5E2%28theta%29++=+0+
-+2%281-cos%5E2%28theta%29%29+-+3sin%5E2%28theta%29++=+0+
-+2sin%5E2%28theta%29+-+3sin%5E2%28theta%29++=+0+
-+5sin%5E2%28theta%29++=+0+
sin%5E2%28theta%29++=+0+
theta=sin%5E-1%280%29
theta=0° and theta=180°