SOLUTION: Without using tables find the values of (a) (tan69° + tan66°)/(1 - tan69°tan66°) (b) (sin45°cos15° + sin15°cos45°)/(sin45°cos15° - sin15°cos45°)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Without using tables find the values of (a) (tan69° + tan66°)/(1 - tan69°tan66°) (b) (sin45°cos15° + sin15°cos45°)/(sin45°cos15° - sin15°cos45°)       Log On


   



Question 1132131: Without using tables find the values of
(a) (tan69° + tan66°)/(1 - tan69°tan66°)
(b) (sin45°cos15° + sin15°cos45°)/(sin45°cos15° - sin15°cos45°)

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
(a)  (tan69° + tan66°)/(1 - tan69°tan66°) = 


             apply the formula  tan(a+b) = %28tan%28a%29+%2B+tan%28b%29%29%2F%281-tan%28a%29%2Atan%28b%29%29


     = tan(69° + 66°) = tan(135°) = tan(180° + 45°) = 1.     ANSWER




(b)  (sin45°cos15° + sin15°cos45°)/(sin45°cos15° - sin15°cos45°) = 


             apply the formula  sin(a+b) = sin(a)*cos(b) + cos(a)*sin(b)  to the numerator;

             apply the formula  sin(a-b) = sin(a)*cos(b) - cos(a)*sin(b)  to the denominator.


      = sin%2845%5Eo%2B15%5Eo%29%2Fsin%2845%5Eo-15%5Eo%29 = sin%2860%5Eo%29%2Fsin%2830%5Eo%29 = %28%28sqrt%283%29%2F2%29%29%2F%28%281%2F2%29%29 = sqrt%283%29.     ANSWER

Solved.