SOLUTION: check the formula is correct for k=1,2, and 3
k
(sigma)n^2 = k(k+1)(2k+1)/6
n=0
use the formula given in the problem above to compute the value of
5
(Sigma) (2m^2+3m-4)
m=0
Algebra ->
Sequences-and-series
-> SOLUTION: check the formula is correct for k=1,2, and 3
k
(sigma)n^2 = k(k+1)(2k+1)/6
n=0
use the formula given in the problem above to compute the value of
5
(Sigma) (2m^2+3m-4)
m=0
Log On
Question 1131970: check the formula is correct for k=1,2, and 3
k
(sigma)n^2 = k(k+1)(2k+1)/6
n=0
use the formula given in the problem above to compute the value of
5
(Sigma) (2m^2+3m-4)
m=0 Answer by Edwin McCravy(20056) (Show Source):
k=1
k=2
k=3
---------------------------------------------
The preceding two steps involved (A) taking out a constant coefficient,
and (B) introducing a multiplier of 1 so we would have a constant
coefficient of -4 to take out. But from here we need two other summation
formulas, which are:
and
Edwin
