SOLUTION: "a cattle train left washington and traveled toward Johannesburg at an average speed of 32 mph. a passenger train left some time later traveling in the same direction at an average
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Question 1131901: "a cattle train left washington and traveled toward Johannesburg at an average speed of 32 mph. a passenger train left some time later traveling in the same direction at an average speed of 40 mph. after traveling for eight hours the passenger train caught up with the cattle train. find the number of the hours the cattle train traveled before the passenger train caught up" Found 2 solutions by josmiceli, ankor@dixie-net.com:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the time in hrs from the
time the cattle train left until the passenger
train departed mi is the distance the passenger
train travels until it catches the cattle train
Start a stopwatch when the passenger train leaves
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Equation for the cattle train: hrs
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check answer: mi/hr
OK
You can put this solution on YOUR website! "a cattle train left washington and traveled toward Johannesburg at an average speed of 32 mph.
a passenger train left some time later traveling in the same direction at an average speed of 40 mph. after traveling for eight hours the passenger train caught up with the cattle train.
find the number of the hours the cattle train traveled before the passenger train caught up"
:
let t = no. of hrs the cattle traveled when the passenger train caught up
When this happens, both trains will have traveled the same distance
Write distance equation (dist = speed * time)
32t = 40*8
32t = 320
t = 320/32
t = 10 hrs travel time of the cattle
