SOLUTION: Alexander has 98 coins. Of the coins 2/7 are nickels, 3/7 are dimes, and tge rest are quaters. What is the ratio of Alexander's nickles to dimes to quaters?
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Question 1131853: Alexander has 98 coins. Of the coins 2/7 are nickels, 3/7 are dimes, and tge rest are quaters. What is the ratio of Alexander's nickles to dimes to quaters? Found 3 solutions by Boreal, stanbon, ikleyn:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! nickels are 2/7 *98 or 28
dimes are 3/7 of 98 or 42
quarters are 28
28:42:28 is the ratio, and all may be divided by 14
2:3:2
You can put this solution on YOUR website! Alexander has 98 coins. Of the coins 2/7 are nickels, 3/7 are dimes, and the rest are quarters. What is the ratio of Alexander's nickles to dimes to quarters?-----
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Must be 1-(2/7+3/7) = 4/7 quarters
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Ratio:: 2:3:4
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Cheers,
Stan H.
You can put this solution on YOUR website! Alexander has 98 coins. Of the coins 2/7 are nickels, 3/7 are dimes, and the rest are quarters.
What is the ratio of Alexander's nickles to dimes to quarters?-----
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Must be 1-(2/7+3/7) = 2/7 quarters
Ratio:: 2:3:2. ANSWER