SOLUTION: helicopter flies from the airport on a course with a bearing of 19degrees. After flying for 105 ​miles, the helicopter flies due east for some time. The helicopter flies bac
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Question 1131837: helicopter flies from the airport on a course with a bearing of 19degrees. After flying for 105 miles, the helicopter flies due east for some time. The helicopter flies back to the airport with a bearing of 223degrees. How far did the helicopter fly on the final leg of its journey? Found 2 solutions by Boreal, ankor@dixie-net.com:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Draw this out
the side that is 105 miles turns east, forming an angle of 109 degrees. The easternmost angle of the track is 47 degrees
Law of Sines
105/sin 47=x/sin 109, where x is the length of the final leg.
105*sin 109/sin 47=x
x=135.75 miles
You can put this solution on YOUR website! helicopter flies from the airport on a course with a bearing of 19degrees.
After flying for 105 miles, the helicopter flies due east for some time.
The helicopter flies back to the airport with a bearing of 223degrees.
How far did the helicopter fly on the final leg of its journey?
:
Draw this out and find the interior angles of the triangle formed by the course of the helicopter, starts at C, 105 mi to A
A: 19 + 90 = 109 degrees
B: 270-223 = 47 degrees
C: 108 - 109 - 47 = 24 degrees
:
a = final leg distance
b = 105 mi
:
Use the law of sines to find a =
:
a =
a = 135.7 mi
