SOLUTION: ΔABC, m∠C = 90º m∠B = 30º CM - angle bisector Find: m∠AMC

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Question 1131759: ΔABC, m∠C = 90º
m∠B = 30º

CM
- angle bisector
Find: m∠AMC

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

ΔABC, m∠ C = 90º
m∠B = 30º

then,m∠ A = 60º

CM- angle bisector, C = 90º id divided into two 45º angles MCA and MCB, and ΔABC into two Δ (ACM and BCM)
since ∠AMC+ is in Δ ACM, and we know two other angles, then
m∠AMC+=180-%2830%2B45%29=180-75=105 º

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

ΔABC, m∠C = 90º
m∠B = 30º

CM
- angle bisector
Find: m∠AMC
That woman is WRONG yet again:!!
Correct answer: ∠AMC = highlight_green%2875%5Eo%29