SOLUTION: Solve the following linear programming problem using the corner-point method. Maximize: P = 3X + 54Y Subject to: 4X + 4Y </= 48 1X + 2Y </= 20 Y >/= 2 X, Y >/= 0

Algebra ->  Probability-and-statistics -> SOLUTION: Solve the following linear programming problem using the corner-point method. Maximize: P = 3X + 54Y Subject to: 4X + 4Y </= 48 1X + 2Y </= 20 Y >/= 2 X, Y >/= 0      Log On


   



Question 1131670: Solve the following linear programming problem using the corner-point method.
Maximize: P = 3X + 54Y
Subject to: 4X + 4Y 1X + 2Y Y >/= 2
X, Y >/= 0

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Your information is confusing.
You have y%3E=2 and y%3E=0.
I'll assume y%3E=2
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4x%2B4y%3C=48
x%2By%3C=12
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x%2B2y%3C=20
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Putting them together,
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Check the function for a maximum at each of the three vertices,
(0,10)
(10,2)
(4,8)
I'll do one, you do the other two,
P=3x%2B54y
So at (0,10),
P%280%2C10%29=3%280%29%2B54%2810%29=0%2B540=540
Now do the same for the other two.