SOLUTION: Phosphorous-32 is used to mark cells in biological experiments. If phosphorous-32 has a continuous daily decay rate of 4.85%, what is the half-life?

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Question 113161This question is from textbook Explorations In College Algebra
: Phosphorous-32 is used to mark cells in biological experiments. If phosphorous-32 has a continuous daily decay rate of 4.85%, what is the half-life? This question is from textbook Explorations In College Algebra

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x="half-life" ___ 1/2=e^((.0483)(-x)) ___ taking the natural log gives ln(.5)=(.0483)(-x)

multiplying by -1 and dividing by .0483 gives -(ln(.5))/.0483=x