Question 1131574: In triangle ABC, AB= 7, BC= 24, and AC= 25. What is the distance from vertex B to side AC? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! Draw your description. Including altitude from B to AC you can call the left segment along AC as x and the right segment along AC as 25-x. Let y be the length of the altitude.
The triangle is a right angled triangle with the right angle at B.
The simplest way to check it is this:
= = (25-24)*(25+24) = 1*49 = 49 = = .
Let H be the distance under the question. Notice that H is nothing else as the altitude of the triangle ABC drawn from
the right angle vertex B to the hypotenuse AC.
Then we have two expressions for the triangle area
Area = = .
It gives H = . ANSWER
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