SOLUTION: The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?
14/13
25/7
4
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14/13
25/7
4
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Question 1131527: The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?
14/13
25/7
4 Found 4 solutions by MathLover1, MathTherapy, greenestamps, ikleyn:Answer by MathLover1(20850) (Show Source):
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The nth term of an arithmetic sequence is:
if the first term of an arithmetic sequence is and the fifteenth term is , we have
so,
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The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?
14/13
25/7
4
Specific term of an AP: --- Substituting
53 = - 3 + 14d ---------- Substituting
56 = 14d ------------ Adding 3 to both sides
d, or common difference =
Being able to use the formal algebraic methods to solve problems like this is important; you might need them for more difficult problems. But for a simple problem like this one, you can do the same calculations without the formal formulas.
The 15th term is 14 terms after the 1st term (15-1 = 14).
The difference between the 15th term and the first term is 56 (53-(-3) = 56).
So the common difference is 56/14 = 4.
There are 14 gaps of equal size between the first and fifteenth terms of arithmetic sequence.
So, each gap, which is the common difference, is = = 4. ANSWER