Question 1131382: The probability that a certain hockey team will win any given game is 0.3697 based on their 13 year win history of 383 wins out of 1036 games played (as of a certain date). Their schedule for November contains 12 games. Let X = number of games won in November.
What is the probability that the hockey team wins 7 games in November? (Round your answer to four decimal places.)
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! This is a binomial 12C7*0.3697^7*0.6303^5, the 12C7 being the number of ways they can win 7 games and then p^x*(1-p)^(n-x)
=0.0744
Binomial distributions are two choices, independent, fixed number and fixed probability.
to choose 3 from 5, it is 5!/3!2!, or 10 different ways.
12C7 is 12!/7!5! multiplied by the two below.
the next part is the probability of success raised to the number of successes desired.
then multiplied by the probability of failure raised to the number of failures.
This gives the probability of exactly 7.
There are binomial tables, and it can also be done on the calculator.
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