SOLUTION: The height in feet of a projectile with an initial velocity of 96 feet per second and an initial height of 256 feet is a function of time in seconds given by h(t) = -16t^2 + 96t +

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Question 1131358: The height in feet of a projectile with an initial velocity of 96 feet per second and an initial height of 256 feet is a function of time in seconds given by
h(t) = -16t^2 + 96t + 256.
(a) Find the maximum height of the projectile._____ft
(b) Find the time t when the projectile achieves its maximum height.
t = ______sec
(c) Find the time t when the projectile has a height of 0 feet.
t =____________sec
Answer by ikleyn(52770) About Me  (Show Source):
You can put this solution on YOUR website!
.

In this site, I prepared the lessons
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
that contain the solutions of similar problems with detailed explanations.

So, read these lessons attentively. Use them as your TEMPLATE.

Then solve your problem in the same way.


        Honestly,  I don't want to be a machine to make calculations for you and/or instead of you.
        It is not my goal at this forum.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.