SOLUTION: 4. Using the following values for x: -2, -1, 0, 1, 2 a. plot and connect the points for this equation: y = x2 + 1 b. plot and connect the points for this equation: y = x

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 4. Using the following values for x: -2, -1, 0, 1, 2 a. plot and connect the points for this equation: y = x2 + 1 b. plot and connect the points for this equation: y = x      Log On


   

Question 1131316: 4. Using the following values for x: -2, -1, 0, 1, 2
a. plot and connect the points for this equation: y = x2 + 1
b. plot and connect the points for this equation: y = x + 1
c. the shapes are different. What do you think accounts for that?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
. Using the following values for
x: -2,+-1, 0, 1, 2+

a. plot and connect the points for this equation:
y+=+x%5E2+%2B+1
x|y
-2|5->y+=+%28-2%29%5E2+%2B+1=5
-1|2->y+=+%28-1%29%5E2+%2B+1=2
0|1->y+=+%280%29%5E2+%2B+1=1
1|2->y+=+%281%29%5E2+%2B+1=2
2|5->y+=+%282%29%5E2+%2B+1=5





b. plot and connect the points for this equation: y+=+x+%2B+1+
x|y
-2|-1->y+=+-2+%2B+1=-1
-1|0->y+=+-1+%2B+1=0
0|1->y+=+0+%2B+1=-1
1|2->y+=+1+%2B+1=2
2|3->y+=+2+%2B+1=3



c. the shapes are different. What do you think accounts for that?
y+=+x%5E2+%2B+1 is a 2nd degree function, graph is a parabola
y+=+x+%2B+1 is 1st degree function, graph is a line