Question 1131278: A wireless store owner takes presale orders for a new smartphone and tablet. He gets 390 preorders for the smartphone and 340 orders for the tablet.The combined sale of the preorders $395,300.If the price of a smartphone and a tablet together is $1,070,find the cost of one smartphone and the cost of one tablet.
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! s = price of a smartphone and t = price of a tablet.
the combined price of the smartphone and the table is therefore s + t = 1070.
he gets 390 orders for the smartphone and 340 orders for the tablet.
the combined price of the orders is 395300.
the formula for this is 390 * s + 340 * t = 395300.
you have two equations that need to be solved simultaneously.
they are:
s + t = 1070
390 * s + 340 * t = 395300
in the first equation, solve for s to get s = 1070 - t.
in the second equation, replace s with 1070 - t to get 390 * (1070 - t) + 340 * t = 395300.
simplify this equation to get 417300 - 390 * t + 340 * t = 395300.
combine like terms to get 417300 - 50 * t = 395300
add 50 * t to both sides of this equation and subtract 395300 from both sides of this equation to get 22000 = 50 * t
solve for t to get t = 22000 / 50 = 440.
that's the price of the tablet.
since s + t = 1070, then s = 1070 - 440 = 630.
that's the price of the smartphone.
the total price for 390 smartphones and 340 tablets is therefore 390 * 630 + 340 * 440 = 395300, confirming the solution is correct.
the cost of one smartphone is 630 and the cost of one table is 440.
that's your solution.
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