SOLUTION: The probability of a successful optical alignment in the assembly of an optical data storage product is 0.629. Assume that the trials are independent.
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Question 1131146: The probability of a successful optical alignment in the assembly of an optical data storage product is 0.629. Assume that the trials are independent.
(Please enter your answers as fractions in lowest terms or as decimals rounded to four decimal places. Thank you!)
a. What is the probability that the first successful alignment requires exactly 7 trials?
b. What is the probability that the first successful alignment requires at most 4 trials?
c. What is the probability that the first successful alignment requires at least 6 trials? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The first 6 don't work with probability each of 0.371
.371^6*0.629=0.0016
at most 4 means 1-probability first is the fifth or 1-(.371^4*0.629)=0.9881
at least 6 means the first 5 don't work and the 6th does, with probability of 0.0044
