SOLUTION: Find two consecutive even integers such that the smaller added to four times the larger gives a sum of 48.

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Question 1131038: Find two consecutive even integers such that the smaller added to four times the larger gives a sum of 48.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Let the smaller even integer be n, and larger consecutive even integer would be n%2B2.
if the smaller added to four times the larger gives a sum of 48, we have
n%2B4%28n%2B2%29=48....solve for n
n%2B4n%2B8=48
5n=48-8
5n=40
n=40%2F5
n=8

find second number
n%2B2=8%2B2=10

so, your numbers are: 8 and 10