SOLUTION: a 70% acid is to be mixed with water to produce a 5 liter mixture containing 28% acid. How many milliliters of water and how many milliliters of the 70% acid solution are needed to

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Question 1130991: a 70% acid is to be mixed with water to produce a 5 liter mixture containing 28% acid. How many milliliters of water and how many milliliters of the 70% acid solution are needed to create the 28% acid solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 70% mixture needed
Let +b+ = liters of water needed
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(1) +a+%2B+b+=+5+ liters
(2) +.7a+%2F+5+=+.28+
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(2) +.7a+=+1.4+
(2) +a+=+2+ liters
and
(1) +2+%2B+b+=+5+
(1) +b+=+3+ liters
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3,000 ml of water and 2,000 ml of 70% mixture are needed