SOLUTION: how many liters of a 5% acid solution should be mixed with 40 liters of 10% acid solution to obtain a mixture that is 8% acid?

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Question 1130978: how many liters of a 5% acid solution should be mixed with 40 liters of 10% acid solution to obtain a mixture that is 8% acid?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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how many liters of a 5% acid solution should be mixed with 40 liters of 10% acid solution to obtain a mixture that is 8% acid?
Let x = amt of 5% solution required
:
a simple mixture equation, decimal equiv of percent
.05x + .10(40) = .08(x+40)
.05x + 4 = .08x + 3.2
.05x - .08x = 3.2 - 4
-.03x = -.8
x = -.8/-.03
x = 262%2F3 liters of 5% soution