SOLUTION: Log(3x+1)+log(1/2)+log(2x-5)=0

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Question 1130976: Log(3x+1)+log(1/2)+log(2x-5)=0
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
log%28%283x%2B1%29%29%2Blog%28%281%2F2%29%29%2Blog%28%282x-5%29%29=0+
log%28%28%283x%2B1%29%281%2F2%29%282x-5%29%29%29=0+.......0=log%2810%2C1%29
log%28%28%283x%2B1%29%281%2F2%29%282x-5%29%29%29=log%2810%2C1%29+
%283x%2B1%29%281%2F2%29%282x-5%29=1+
%283x%2B1%29%282x-5%29=1%2F%281%2F2%29+
6x%5E2-15x%2B2x-5=2+
6x%5E2-13x-5=2+
6x%5E2-13x-5-2=0+
6x%5E2-13x-7=0+


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-13%29+%2B-+sqrt%28+%28-13%29%5E2-4%2A6%2A%28-7%29+%29%29%2F%282%2A6%29+
x+=+%2813+%2B-+sqrt%28169%2B168+%29%29%2F12+
x+=+%2813+%2B-+sqrt%28+337+%29%29%2F12+

solutions:
x+=+13%2F12+%2B+sqrt%28337%29%2F12+
x+=+13%2F12+-+sqrt%28337%29%2F12+