SOLUTION: Pennies are stacked on a table so that on the first day there is one penny in the stack and each day after that the number of pennies in the stack is doubled. On what day will the
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Question 1130907: Pennies are stacked on a table so that on the first day there is one penny in the stack and each day after that the number of pennies in the stack is doubled. On what day will the stack contain more than $1.00 worth of pennies? Found 2 solutions by Shin123, MathTherapy:Answer by Shin123(626) (Show Source):
You can put this solution on YOUR website! On day 1, there are 2^0 pennies. On day 2, there are 2^1 pennies. And so on. So basically, on day a, there are pennies. So we need to find the smallest integer a such as . 2^6 is 64 and 2^7 is 128. If a-1 is 7, than on day 8, there is more than $1.00 worth of pennies.
You can put this solution on YOUR website!
Pennies are stacked on a table so that on the first day there is one penny in the stack and each day after that the number of pennies in the stack is doubled. On what day will the stack contain more than $1.00 worth of pennies?
