SOLUTION: A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 75% .He wants to use all three solu

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Question 1130773: A chemist has three different acid solutions. The first acid solution contains
20%
acid, the second contains
30%
and the third contains
75%
.He wants to use all three solutions to obtain a mixture of 48
liters containing
50%
acid, using 2
times as much of the
75%
solution as the 30%
solution. How many liters of each solution should be used?

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Not like that. You know how to present your exercise problem.

A very similar example was recently solved thoroughly.

Your current example problem #1130773 answer:
12 liters of 20%
12 liters of 30%
24 liters of 75%