SOLUTION: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face val
Algebra ->
Probability-and-statistics
-> SOLUTION: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face val
Log On
Question 1130638: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
the probability of each of the following events:
A: a sum greater than 5
B: The sum is divisible by 5 or 6 (or both) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! sum equal to 6 has probability (5/36)
7--1/6 or 6/36
8--5/36
9--4/36
10--3/36
11--2/36
12--1/36
answer to a is 26/36 or 13/18
divisible by 5 includes 5 and 10. This probability is 4/36 and 3/36
by 6 includes 6 and 12 with probability 5/36 and 1/36. Those probabilities are 13/36 when all added.
