SOLUTION: The fuel efficiency for a certain midsize car is given by
E(v) = −0.014v2 + 1.176v + 3.2
where E(v) is the fuel efficiency in miles per gallon for a car traveling v miles p
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-> SOLUTION: The fuel efficiency for a certain midsize car is given by
E(v) = −0.014v2 + 1.176v + 3.2
where E(v) is the fuel efficiency in miles per gallon for a car traveling v miles p
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Question 1130540: The fuel efficiency for a certain midsize car is given by
E(v) = −0.014v2 + 1.176v + 3.2
where E(v) is the fuel efficiency in miles per gallon for a car traveling v miles per hour.
(a) What speed will yield the maximum fuel efficiency? Round to the nearest mile per hour. mph
(b) What is the maximum fuel efficiency for this car? Round to the nearest mile per gallon. mpg Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! he fuel efficiency for a certain midsize car is given by
E(v) = −0.014v^2 + 1.176v + 3.2
where E(v) is the fuel efficiency in miles per gallon for a car traveling v miles per hour.
(a) What speed will yield the maximum fuel efficiency? Round to the nearest mile per hour. mph
E(v) = .014v^2 + 1.176v + 3.2
Max efficiency occurs on the axis of symmetry using the formula x =-b/(2a)
Where: a= -.014; b= 1.176
v =
v =
v = +42 mph gives max efficiency
:
(b) What is the maximum fuel efficiency for this car? Round to the nearest mile per gallon. mpg
v = 42
E(v) = .014(42^2) + 1.176(42) + 3.2
E(v) = .014(1764) + 49.4 + 3.2
E(v) = -24.7 + 49.4 + 3.2
E(v) = 27.9 ~ 28 mpg
