SOLUTION: Break-downs occur on an old car with a rate of 6 break-downs every four weeks. The owner of the car is planning to have a trip on his car for 4 days. What is the probability that h
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-> SOLUTION: Break-downs occur on an old car with a rate of 6 break-downs every four weeks. The owner of the car is planning to have a trip on his car for 4 days. What is the probability that h
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Question 1130510: Break-downs occur on an old car with a rate of 6 break-downs every four weeks. The owner of the car is planning to have a trip on his car for 4 days. What is the probability that he will return home without experiencing a car break-down? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! That is 6 per 28 days, so that would be 6/7 per four days, dividing both by 7.
parameter is 6/7
probability of 0 is e^(-6/7)=0.4244
