SOLUTION: a contractor mixes concrete from bags of pre-mix for small jobs how many bags with 6% cement should he mix with 5 bags of 18.8% cement to produce a mix containing 10% cement?
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Question 1130150: a contractor mixes concrete from bags of pre-mix for small jobs how many bags with 6% cement should he mix with 5 bags of 18.8% cement to produce a mix containing 10% cement? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
Since the solution and the answer by @josgarithmetic are both T O T A L L Y W R O N G, I came to fix it.
Below find my correct solution.
x bags of 6% cement
5 bags of 18.8% cement
want 10% cement
= (*)
It is your basic equation to solve.
18.8*5-50 =
x =
x = 11 bags of the 6% cement mix. AnswerCHECK. Left side of the equation (*) 0.06*11 + 0.188*5 = 1.6 is the pure cement amount
Right side of the equation (*) 0.1*(11+5) = 1.6 is the pure cement amount. ! Both sides are equal - the solution is CORRECT !
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