SOLUTION: Emma paid the $ 8.12 bill for her lunch with 194 coins consisting of pennies, nickels, and dimes. If the number of nickels plus the number of dimes was equal to the number of

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Emma paid the $ 8.12 bill for her lunch with 194 coins consisting of pennies, nickels, and dimes. If the number of nickels plus the number of dimes was equal to the number of       Log On

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Question 1130080: Emma paid the
$
8.12 bill for her lunch with
194 coins consisting of pennies, nickels, and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies, then how many coins of each type did she use?

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n%2Bd=p%2Cn%2Bd%2Bp=194%2C5n%2B10d%2Bp=812%29

p%2Bp=194
2p=194
highlight%28highlight%28p=97%29%29------PENNIES


5n%2B10d=812-97
5n%2B10d=715


system%28n%2Bd=97%2C5n%2B10d=715%29

simplersystem
system%28n%2Bd=97%2Cn%2B2d=143%29

d=143-97
highlight%28highlight%28d=46%29%29-------DIMES
.
YOU CAN FIND THE NICKELS BY DIFFERENCE.
GIVEN 194 TOTAL COINS