SOLUTION: factor quadratic trinomials completely 3p2-11p-20 I do not understand how to do this. My grand daughter notes are sketchy at best. I need all the help I can get on this

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Question 1130010: factor quadratic trinomials completely 3p2-11p-20 I do not understand how to do this. My grand daughter notes are sketchy at best. I need all the help I can get on this
Found 2 solutions by MathLover1, josgarithmetic:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

3p%5E2-11p-20 .....write -11p as %2B4p-15p
3p%5E2%2B4p-15p-20.............group
%283p%5E2-15p%29%2B%284p-20%29
3p%28p-5%29%2B4%28p-5%29
%283p+%2B+4%29+%28p+-+5%29

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
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factor quadratic trinomials completely 3p2-11p-20 I do not understand how
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Not as 3p2-11p-20
but
as 3p^2-11p-20


3p%5E2-11p-20 
(3p   ? )(p  ? )

You want to find two unknown numbers so that their product is -20 and so when you would perform the multiplication of the two binomials and simplify, the p term has coefficient -11. You can make all possible combinations and test each of them until the one that works is found.

Note that 20=20%2A1=2%2A10=4%2A5.

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( +4 and -5 will work).